Question
Question: \(\sec h(\pi i) + co\text{sech}\left( \frac{\pi}{2}i \right)\) equals...
sech(πi)+cosech(2πi) equals
A
1−i
B
−1+i
C
−1−i
D
1+i
Answer
−1−i
Explanation
Solution
sech(πi)+cosech(2πi)= secπ−icosec 2π=−1−i
sech(πi)+cosech(2πi) equals
1−i
−1+i
−1−i
1+i
−1−i
sech(πi)+cosech(2πi)= secπ−icosec 2π=−1−i