Solveeit Logo
Login

Question

Question: \[(\sec A + \tan A - 1)(\sec A - \tan A + 1) - 2\tan A =\]...

(sec⁡A+tan⁡A−1)(sec⁡A−tan⁡A+1)−2tan⁡A=(\sec A + \tan A - 1)(\sec A - \tan A + 1) - 2\tan A =

A

sec⁡A\sec A

B

2sec⁡A2\sec A

C

0

D

1

Answer

0

Explanation

Solution

(sec⁡A+tan⁡A−1)(sec⁡A−tan⁡A+1)−2tan⁡A(\sec A + \tan A - 1)(\sec A - \tan A + 1) - 2\tan A

=(sec⁡2A−tan⁡2A)+sec⁡A+tan⁡A−sec⁡A+tan⁡A−1−2tan⁡A=0= (\sec^{2}A - \tan^{2}A) + \sec A + \tan A - \sec A + \tan A - 1 - 2\tan A = 0

(∵sec⁡2A−tan⁡2A=1)(\because\sec^{2}A - \tan^{2}A = 1)