((\sec 2A + 1)\sec^{2}A =) | MATH - FUNDAMENTAL TRIGONOMETRICAL | SolveeIt

$(\sec 2A + 1)\sec^{2}A =$

$\sec A$

$2\sec A$

$\sec 2A$

$2\sec 2A$

Answer

$2\sec 2A$

Explanation

$(\sec 2A + 1)\sec^{2}A = \left( \frac{1 + \tan^{2}A}{1 - \tan^{2}A} + 1 \right)(1 + \tan^{2}A)$

$= \frac{2(1 + \tan^{2}A)}{1 - \tan^{2}A} = 2\sec 2A.$

Question: \((\sec 2A + 1)\sec^{2}A =\)...