Question

Schotten-Baumann reaction is a reaction of phenols with

• A. benzoyl chloride and NaOH
• B. acetyl chloride and NaOH
• C. salicylic acid and cone. $H_2SO_4$
• D. acetyl chloride and cone. $H_2SO_4$

Answer 1

Answer: (A)

benzoyl chloride and NaOH

Answer 2

$C_6H_5COCI + C_6H_5OH \xrightarrow [pyridine] {ANaOH} C_6H_5C00C_6H_5 + HCI$