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Question

Physics Question on Keplers Laws

satellite revolve in radius R has a time period of revolution T. Find time period of a satellite if orbital radius is 9R?

A

33T3\sqrt{3}T

B

9T

C

27 T

D

93T9\sqrt{3}T

Answer

27 T

Explanation

Solution

According to Kepler's law of periods T2R3T^{2}\,\propto\,R^{3} So,T1T2=(R1R2)32\,\Rightarrow\, \frac{T_{1}}{T_{2}}=\left(\frac{R_{1}}{R_{2}}\right)^{\frac{3}{2}} TT2=(R9R)32=127[T1=T]\Rightarrow\, \frac{T}{T_{2}}=\left(\frac{R}{9R}\right)^{\frac{3}{2}}\,=\frac{1}{27}\,\left[\because \,T_{1}=T\right] T2=27TT_{2}=27T