Question

Sand is being dropped from a stationary dropper at a rate of 0.5 kgs–1 on a conveyor belt moving with a velocity of 5 ms–l. The power needed to keep the belt moving with the same velocity will be

• A. 1.25 W
• B. 2.5 W
• C. 6.25 W
• D. 12.5 W

Answer 1

Answer: (D)

12.5 W

Answer 2

The correct option is(D): 12.5 W.

$\frac{dm}{dt}=0.5\,kg/s$

$v=5m/s$

F=2.5

$P=F+\overline{v}$

=(2.5)(5)W=12.5 W