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Question: Salt cake\(N{{a}_{2}}S{{O}_{4}}\) is prepared as follows: \[2NaCl+{{H}_{2}}S{{O}_{4}}\,\,\to \,\,...

Salt cakeNa2SO4N{{a}_{2}}S{{O}_{4}} is prepared as follows:
2NaCl+H2SO4Na2SO4+2HCL2NaCl+{{H}_{2}}S{{O}_{4}}\,\,\to \,\,N{{a}_{2}}S{{O}_{4}}+2HCL
How much 8080% pure salt cake could be produced from 100.0 g100.0\text{ }g of 9090% pure salt in the above reaction?
A. 43.92 g43.92\text{ }g
B. 68.62 g68.62\text{ }g
C. 87.84 g87.84\text{ }g
D. 136.25 g136.25\text{ }g

Explanation

Solution

Firstly, students must know what salt cake is in order to solve the question.Salt cake is a crude form obtained by reaction of sulphuric acid on common salt (NaCl)\left( NaCl \right). 2 moles of pure salt are forming 1 mole of Na2SO4N{{a}_{2}}S{{O}_{4}} (salt cake). We need to find the number of molar masses of NaClNaCl and then equate it in an equation form to obtain the answer.

Complete step by step answer:
First, we find the molar masses of NaClNaCl and Na2SO4N{{a}_{2}}S{{O}_{4}}
Molar mass of NaCl= 23+35.5NaCl=\text{ }23+35.5
58.5 g/mol\Rightarrow 58.5\text{ }g/mol
Next the molar mass of Na2So4=23×2+32+4×16N{{a}_{2}}S{{o}_{4}}\,=\,23\times 2+32+4\times 16
142 g/mol\Rightarrow 142\text{ }g/mol
Now,
100g100g of 9090% pure NaClNaCl corresponds to (90/100)×100×58.5=1.54\left( 90/100 \right)\times 100\times 58.5=1.54 moles. So, the number of moles of Na2SO4N{{a}_{2}}S{{O}_{4}} formed from 1.54 moles of NaClNaCl (common salt) is 1.542=0.77\dfrac{1.54}{2}=0.77 moles.
Since 2 moles of NaClNaCl gives 1 mole of Na2SO4N{{a}_{2}}S{{O}_{4}}. So,
1 mole of NaClNaCl gives 12\dfrac{1}{2} moles of Na2SO4N{{a}_{2}}S{{O}_{4}}.
Therefore, 1.54 moles of NaClNaCl gives 0.77 moles of Na2SO4N{{a}_{2}}S{{O}_{4}}.
The mass of Na2SO4N{{a}_{2}}S{{O}_{4}} obtained is0.77×142= 109.8 g0.77\times 142=\text{ }109.8\text{ }g
But as you can see, it is given in the question that the salt cake is8080% pure. Hence, the mass of the salt cake that can be obtained is given by:
(109.8/80)×100= 136.25 g\left( 109.8/80 \right)\times 100=\text{ }136.25\text{ }g
Thus, we get the amount of 8080%pure salt cake produced to be136.25g136.25g.

Thus, Option A is correct.

Note:
As stated earlier salt cake is impure sodium sulphate, especially obtained by the interaction of sulphuric acid and common salt in the synthesis of hydrochloric acid; which is chiefly used in the manufacture of glasses, ceramic glazes, soaps, etc. Students must check if the reaction is balanced or not so that the number of moles can be correctly found out.