Question
Question: Salt cake\(N{{a}_{2}}S{{O}_{4}}\) is prepared as follows: \[2NaCl+{{H}_{2}}S{{O}_{4}}\,\,\to \,\,...
Salt cakeNa2SO4 is prepared as follows:
2NaCl+H2SO4→Na2SO4+2HCL
How much 80 pure salt cake could be produced from 100.0 g of 90 pure salt in the above reaction?
A. 43.92 g
B. 68.62 g
C. 87.84 g
D. 136.25 g
Solution
Firstly, students must know what salt cake is in order to solve the question.Salt cake is a crude form obtained by reaction of sulphuric acid on common salt (NaCl). 2 moles of pure salt are forming 1 mole of Na2SO4 (salt cake). We need to find the number of molar masses of NaCl and then equate it in an equation form to obtain the answer.
Complete step by step answer:
First, we find the molar masses of NaCl and Na2SO4
Molar mass of NaCl= 23+35.5
⇒58.5 g/mol
Next the molar mass of Na2So4=23×2+32+4×16
⇒142 g/mol
Now,
100g of 90 pure NaCl corresponds to (90/100)×100×58.5=1.54 moles. So, the number of moles of Na2SO4 formed from 1.54 moles of NaCl (common salt) is 21.54=0.77 moles.
Since 2 moles of NaCl gives 1 mole of Na2SO4. So,
1 mole of NaCl gives 21 moles of Na2SO4.
Therefore, 1.54 moles of NaCl gives 0.77 moles of Na2SO4.
The mass of Na2SO4 obtained is0.77×142= 109.8 g
But as you can see, it is given in the question that the salt cake is80 pure. Hence, the mass of the salt cake that can be obtained is given by:
(109.8/80)×100= 136.25 g
Thus, we get the amount of 80pure salt cake produced to be136.25g.
Thus, Option A is correct.
Note:
As stated earlier salt cake is impure sodium sulphate, especially obtained by the interaction of sulphuric acid and common salt in the synthesis of hydrochloric acid; which is chiefly used in the manufacture of glasses, ceramic glazes, soaps, etc. Students must check if the reaction is balanced or not so that the number of moles can be correctly found out.