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Physics Question on doppler effect

S1 & S2 are sources of the sound of frequency 656 Hz. S1 is moving along OP and S2 is moving on the circle in an anticlockwise direction with a constant speed of 4√2 m\s. P is a detector that is fixed. Select the correct options (Vsound=300m\s)

circle in an anticlockwise direction

A

When S2 is at Q, Then frequency it detected by the detector is approximately 647 Hz.

B

When S2 is at Q, Then frequency it detected by the detector is 327 Hz.

C

When S2 is at R and S1 is coming toward P with a velocity of 4m/s, Then the beat frequency it detected by the detector is 8.86 Hz.

D

When S2 is at R and S1 is coming toward P with a velocity of 4m/s, Then the beat frequency it detected by the detector is 2.56 Hz.

Answer

When S2 is at Q, Then frequency it detected by the detector is approximately 647 Hz.

Explanation

Solution

The correct options are (A) and (C).

beat frequency

f=656×300304f'=\frac{656\times300}{304}

f=647.36Hzf'=647.36\,Hz

Hence, Option (A) is correct.

From S2 , f=656[300300+42cos90]f'=656\,[\frac{300}{300+4\sqrt2\,cos\,90}]

f=656f'=656

From S1, f=656[3003004]f''=656\,[\frac{300}{300-4}]

f=664.86f''=664.86

Beat frequency = fff''-f' = 664.86656664.86-656 = 8.86 Hz
br>Hence, Option (C) is also correct.