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Question

Mathematics Question on types of differential equations

(S1):limn1n2(2+4+6+....+2n)=1(S1) : lim_{n→∞}\frac{1}{ n ^2} ( 2 + 4 + 6 + . . . . + 2n) = 1
(S2):limn1n16(115+215+315+....+n15)=116(S2): lim_n→∞\frac{1}{n^{16}}( 1^15 +2^15 +3^15 + . . . . + n^15 ) = \frac{1}{16}

A

Only (S1) is true

B

Only (S2) is true

C

Both (S1) and (S2) are true

D

Both (S1) and (S2) are false

Answer

Both (S1) and (S2) are true

Explanation

Solution

The correct option is(C): Only (S2) is true