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Question

Mathematics Question on Arithmetic Progression

Sn=13+23+33+...+n3S_n = 1^3 + 2^3 + 3^3 + ... + n^3 and Tn=1+2+3+4......nT_n = 1 + 2 + 3 + 4 ......n

A

Sn=Tn3S_n = T^3_n

B

Sn=Tn2S_n = T_{n^2}

C

Sn=Tn2S_n = T_{n}^2

D

Sn=Tn3S_n = T_{n}^3

Answer

Sn=Tn2S_n = T_{n}^2

Explanation

Solution

Put n = 2 and verify the options.