Question
Question: \[{{S}_{1}}\] and \[{{S}_{2}}\] are the two coherent point sources of light located in the XY plane ...
S1 and S2 are the two coherent point sources of light located in the XY plane at points (0,0) and (0,3λ) respectively. Here λ is the wavelength of the light. At which one of the following points (given as coordinates), the intensity of interference will be maximum?
A. (3λ,0)
B. (4λ,0)
C. (5λ/4,0)
D. (2λ/3,0)
Solution
In this question we are asked to calculate the maximum intensity of interference. We know that the intensity of light will be maximum if the light reaching from path 1 and 2 is equal to λ. Therefore, using this concept we will first calculate the path difference between the light and equate the path difference with condition for maximum intensity.
Formula used:
Δx=S2P−S1P
Complete answer:
We know that, at point P the intensity would be maximum if the light from path 1 and path 2 is equal to λ. Therefore,
From the diagram given below, we can say path difference in between the light is given by,

Δx=S2P−S1P ……………….. (1)
Where S1 and S2 are the distances.
From the diagram given above we can say that
S1P=(x−0)−(0−0)=x
Similarly S2P can be given as
S2P=(0−x)2+(3λ−0)2
S2P=x2+9λ2
After substituting the calculated values in equation (1)
We get,
Δx=x2+9λ2−x2
Now we know that for maximum intensity
Δx=λ
Therefore, we can say that
λ=x2+9λ2−x2
Therefore,
x2+9λ2=x2+y2+2λx
On solving,
We get,
x=2λ8λ2
x=4λ
Therefore, the coordinates would be (4λ,0)
So, the correct answer is “Option B”.
Note:
The path difference is basically the distance travelled by two waves from their respective sources. It is used to describe the difference in degrees or radians When two or more alternating quantities reach their maximum high or zero. The intensity of interference is the difference between two waves.