Question
Question: Rs 18,000 is kept for \(2\dfrac{1}{2}\) at 10 percent compounded annually. What is the interest and ...
Rs 18,000 is kept for 221 at 10 percent compounded annually. What is the interest and final amount received?
Solution
Now we know that principal amount is 18, 000, time is 221 and rate of interest is 10 percent per annum. Now we will first calculate the amount for 2 years with the formula A=P(1+100r)t now once we have the amount we will use simple interest formula A=100P(1+rt) with time as 21 years and rate of interest 10 percent.
Complete step by step answer:
Now we are given that Rs 18,000 is kept for 221 at 10 percent compounded annually.
Now we have principal amount Rs 18,000, time is 221 and the rate of interest is 10 percent.
Now since time is not an integer we will find the amount received after 2 years by compound interest
Now since the interest is compounded per year, we can use simple interest to find the amount after 21 years.
Now we know that amount received by compound interest is given by A=P(1+100r)t .
Hence amount after 2 years will be
A=18000(1+10010)2⇒A=18000(100100+10)2⇒A=18000(100110)2⇒A=18000(1011)2
⇒A=18000(100121)
⇒A=180×121
∴A=21780
Hence we have amount received after 2 years is 21780.
Now let us calculate the simple interest in 21 years
We know the amount of simple interest is given by A=P+100P×r×t
The amount after 2 years is our principal amount hence from equation (1) we get
Principal amount is 21780.
Now interest is 10 percent
And time is 21 years
Hence the amount received is