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Question: Rs 18,000 is kept for \(2\dfrac{1}{2}\) at 10 percent compounded annually. What is the interest and ...

Rs 18,000 is kept for 2122\dfrac{1}{2} at 10 percent compounded annually. What is the interest and final amount received?

Explanation

Solution

Now we know that principal amount is 18, 000, time is 2122\dfrac{1}{2} and rate of interest is 10 percent per annum. Now we will first calculate the amount for 2 years with the formula A=P(1+r100)tA=P{{\left( 1+\dfrac{r}{100} \right)}^{t}} now once we have the amount we will use simple interest formula A=P(1+rt)100A=\dfrac{P\left( 1+rt \right)}{100} with time as 12\dfrac{1}{2} years and rate of interest 10 percent.

Complete step by step answer:
Now we are given that Rs 18,000 is kept for 2122\dfrac{1}{2} at 10 percent compounded annually.
Now we have principal amount Rs 18,000, time is 2122\dfrac{1}{2} and the rate of interest is 10 percent.
Now since time is not an integer we will find the amount received after 2 years by compound interest
Now since the interest is compounded per year, we can use simple interest to find the amount after 12\dfrac{1}{2} years.
Now we know that amount received by compound interest is given by A=P(1+r100)tA=P{{\left( 1+\dfrac{r}{100} \right)}^{t}} .
Hence amount after 2 years will be
A=18000(1+10100)2 A=18000(100+10100)2 A=18000(110100)2 A=18000(1110)2 \begin{aligned} & A=18000{{\left( 1+\dfrac{10}{100} \right)}^{2}} \\\ & \Rightarrow A=18000{{\left( \dfrac{100+10}{100} \right)}^{2}} \\\ & \Rightarrow A=18000{{\left( \dfrac{110}{100} \right)}^{2}} \\\ & \Rightarrow A=18000{{\left( \dfrac{11}{10} \right)}^{2}} \\\ \end{aligned}
A=18000(121100)\Rightarrow A=18000\left( \dfrac{121}{100} \right)
A=180×121\Rightarrow A=180\times 121
A=21780\therefore A=21780
Hence we have amount received after 2 years is 21780.
Now let us calculate the simple interest in 12\dfrac{1}{2} years
We know the amount of simple interest is given by A=P+P×r×t100A=P+\dfrac{P\times r\times t}{100}
The amount after 2 years is our principal amount hence from equation (1) we get
Principal amount is 21780.
Now interest is 10 percent
And time is 12\dfrac{1}{2} years
Hence the amount received is

& A=21780+\dfrac{21780\times 10\times \dfrac{1}{2}}{100} \\\ & \Rightarrow A=21780+1089 \\\ & \therefore A=22869 \\\ \end{aligned}$$ Hence the final amount received after $2\dfrac{1}{2}$ years is 22869 Rs. Now interest is final amount – principal amount Hence Interest = 22869 – 18000 = 4869 **Hence the interest is 4869 Rs.** **Note:** Note that the formula of compound interest is $P{{\left( 1+\dfrac{r}{100n} \right)}^{nt}}$ where n is number of times interest is compounded in a year. Since we have interest is compounded annually we have taken n = 1. Which is nothing but formula for compound interest compounded per year. Also while substituting always note that rate of interest is per years and time is also in years.