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Question

Mathematics Question on Continuity and differentiability

Rolle Theorem f(x) = sin x + cos x. Find c ε [0,2,π]

Answer

To apply the Rolle's theorem to the function f(x)=sinx+cosxf(x) = sin x + cos x in the interval [0,2π][0, 2\pi],

we need to check the conditions of the theorem: Continuity:

The function f(x)=sinx+cosxf(x) = sin x + cos x is continuous on the interval [0,2π][0, 2\pi] as both sin x and cos x are continuous functions. Differentiability:

The function f(x)=sinx+cosxf(x) = sin x + cos x is differentiable on the interval (0,2π)(0, 2\pi) as both sin x and cos x are differentiable functions.

Function values: We have f(0)=sin0+cos0=0f(0) = sin 0 + cos 0 = 0 and f(2π)=sin(2π)+cos(2π)=0f(2π) = sin (2π) + cos (2π) = 0.

Since all the conditions of Rolle's theorem are satisfied, there exists at least one point c in the interval (0,2π)(0, 2\pi) such that f(c)=0f'(c) = 0.

To find the value of c, we need to find the derivative of f(x) and set it equal to zero: f(x)=cosxsinxf'(x) = cos x - sin x Setting f(x)=0f'(x) = 0,

we have cosxsinx=0cos x - sin x = 0. Simplifying further, cosx=sinxcos x = sin x.

This equation is satisfied at x=3π4x = \frac{3π}{4}.

Therefore, in the interval [0,2π][0, 2\pi], there exists at least one point c=3π4c = \frac{3π}{4} such that f(c)=0f'(c) = 0.