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Question

Physics Question on Gravitation

Rohini satellite at a height of 500km500 \,km and INSAT-B at a height of 3600km3600\, km from surface of earth, then relation between their orbital velocity (vR,vI)\left(v_{R}, v_{I}\right) is

A

(vR>vI)\left(v_{R} > v_{I}\right)

B

(vR<vI)\left(v_{R}< v_{I}\right)

C

(vR=vI)\left(v_{R}=v_{I}\right)

D

No relation

Answer

(vR>vI)\left(v_{R} > v_{I}\right)

Explanation

Solution

Orbital velocity of a satellite is given by vo=GMerv_{o}=\sqrt{\frac{G M_{e}}{r}} where G=G= gravitational constant. Me=M_{e}= mass of the earth r=r= distance of the satellite from the centre of the earth vo1r\therefore v_{o} \propto \frac{1}{\sqrt{r}} As the distance of INSAT-B from the centre of the earth is greater than the distance of Rohini from the centre of the earth vR>vI\therefore v_{R} > v_{I}