Question

Rms value of the saw-tooth voltage of peak value V₀ as shown in

• A.
• B.
• C.
• D.

Answer 1

Answer: (C)

Answer 2

V(t) = V₀ + $\frac { 2 \mathrm {~V} _ { 0 } } { \mathrm {~T} } \times \mathrm { t }$

V_rms =

$\sqrt { \frac { \mathrm { V } _ { 0 } ^ { 2 } \mathrm {~T} + \frac { 4 \mathrm {~V} _ { 0 } ^ { 2 } \mathrm {~T} } { 3 } - 2 \mathrm {~V} _ { 0 } ^ { 2 } \mathrm {~T} } { \mathrm {~T} } }$

= $\frac { V _ { 0 } } { 3 }$