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Question

Question: \[\Rightarrow\]...

⇒\Rightarrow

A

A≠B≠CA \neq B \neq C

B

x2+1(2x−1)(x2−1)=A(2x−1)+Bx+1+Cx−1\frac{x^{2} + 1}{(2x - 1)(x^{2} - 1)} = \frac{A}{(2x - 1)} + \frac{B}{x + 1} + \frac{C}{x - 1}

C

x2+1=A(x2−1)+B(2x−1)(x−1)+C(x+1)(2x−1)x^{2} + 1 = A(x^{2} - 1) + B(2x - 1)(x - 1) + C(x + 1)(2x - 1)

D

0

Answer

0

Explanation

Solution

⇒\Rightarrow

(a+2b)2=16ab⇒(a + 2b)^{2} = 16ab \Rightarrow= 0.