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Question

Question: \(\Rightarrow\)<!-- -->18 is....

⇒\Rightarrow18 is.

A

A rational number

B

An irrational number

C

A prime number

D

None of these

Answer

An irrational number

Explanation

Solution

=32(6−3)6−3−43(6−2)6−2+6(3−2)3−2= \frac{3\sqrt{2}(\sqrt{6} - \sqrt{3})}{6 - 3} - \frac{4\sqrt{3}(\sqrt{6} - \sqrt{2})}{6 - 2} + \frac{\sqrt{6}(\sqrt{3} - \sqrt{2})}{3 - 2}

=2(6−3)−3(6−2)+6(3−2)= \sqrt{2}(\sqrt{6} - \sqrt{3}) - \sqrt{3}(\sqrt{6} - \sqrt{2}) + \sqrt{6}(\sqrt{3} - \sqrt{2}) which is irrational.