QuestionReportQuestion: \[\Rightarrow\]...⇒\Rightarrow⇒A0B1C−1+3i=(−B2−C2+B2−C)+i32(C−2B)- 1 + \sqrt{3}i = \left( - \frac{B}{2} - \frac{C}{2} + \frac{B}{2} - C \right) + \frac{i\sqrt{3}}{2}(C - 2B)−1+3i=(−2B−2C+2B−C)+2i3(C−2B)D⇒\Rightarrow⇒Answer1ExplanationSolution⇒\Rightarrow⇒ x=52=25x = 5^{2} = 25x=52=25.