Question

Resistances of 6 ohm each are connected in the manner shown in adjoining figure. With the current 0.5 ampere as shown in figure, the potential difference $V_{P} - V_{Q}$ is

• A. 3.6 V
• B. 6.0 V
• C. 3.0 V
• D. 7.2 V

Answer 1

Answer: (C)

3.0 V

Answer 2

$V_{p} - V_{q} = \left( \frac{6}{3} + \frac{12 \times 6}{12 + 6} \right)(0.5) = (2 + 4)(0.5) = 3V$