Solveeit Logo

Question

Physics Question on Electromagnetic induction

Resistance of tungsten wire at 150^{\circ}C is 133Ω133 \Omega. Its resistance temperature coefficient is 0.00450.0045^{\circ}C. The resistance of the wire at 500^{\circ}C will be

A

180Ω180 \Omega

B

225Ω225 \Omega

C

258Ω258 \Omega

D

317Ω317 \Omega

Answer

258Ω258 \Omega

Explanation

Solution

R150R500=[1+α(150)][1+α(500)]\frac {R_{150}}{R_{500}} = \frac {[1 + \alpha (150)]}{[1 + \alpha (500)]} Given, R150=133Ωandα=0.045C,R_{150} = 133 \Omega \, and \, \alpha = 0.045 \, ^{\circ}C, 133R500=1+0.0045×1501+0.0045×500=1.6753.25\therefore \, \, \, \, \, \, \frac {133}{R_{500}}= \frac {1 + 0.0045 \times 150}{1 + 0.0045 \times 500}= \frac {1.675}{3.25} R500=3.25×1331.675258Ω\Rightarrow \, \, \, \, \, \, \, R_{500} = \frac {3.25 \times 133}{1.675} \approx 258 \Omega