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Question: Representing the stopping potential V along y-axis and (1/λ) along x-axis for a given photocathode, ...

Representing the stopping potential V along y-axis and (1/λ) along x-axis for a given photocathode, the curve is a straight line, the slope of which is equal to –

A

e/hc

B

hc/e

C

ec/h

D

he/c

Answer

hc/e

Explanation

Solution

E = φ + eV

eV = – φ

V = hce\frac { \mathrm { hc } } { \mathrm { e } } × 1λ\frac { 1 } { \lambda } – ϕe\frac { \phi } { \mathrm { e } }

Slope = hce\frac { \mathrm { hc } } { \mathrm { e } }