Question
Mathematics Question on Relations and Functions
Relation R on the set A=1,2,3,…,13,14 defined as R=(x,y):3x−y=0 is:
A
Reflexive, symmetric and transitive
B
Reflexive and transitive but not symmetric
C
Neither reflexive nor symmetric but transitive
D
Neither reflexive nor symmetric nor transitive
Answer
Neither reflexive nor symmetric but transitive
Explanation
Solution
The given relation is R=(x,y):3x−y=0.
- Reflexivity: For R to be reflexive, (x,x) must satisfy 3x−x=0 for all x∈A. However, 3x−x=2x=0 for x=0.
Hence, R is not reflexive. - Symmetry: For R to be symmetric, if (x,y)∈R, then (y,x) must also belong to R.
Check: 3x−y=0⟹3y−x=0 for x=y. Hence, R is not symmetric. - Transitivity: For R to be transitive, if (x,y)∈R and (y,z)∈R, then (x,z) must also belong to R.
Check: 3x−y=0 and 3y−z=0⟹3(3x)−z=0⟹9x−z=0, which satisfies the condition. Hence, R is transitive.
Thus, the relation R is neither reflexive nor symmetric but transitive.