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Question

Mathematics Question on Relations and Functions

Relation RR on the set A=1,2,3,,13,14A = \\{1, 2, 3, \ldots, 13, 14\\} defined as R=(x,y):3xy=0R = \\{(x, y) : 3x - y = 0\\} is:

A

Reflexive, symmetric and transitive

B

Reflexive and transitive but not symmetric

C

Neither reflexive nor symmetric but transitive

D

Neither reflexive nor symmetric nor transitive

Answer

Neither reflexive nor symmetric but transitive

Explanation

Solution

The given relation is R=(x,y):3xy=0R = \\{(x, y) : 3x - y = 0\\}.

  • Reflexivity: For RR to be reflexive, (x,x)(x, x) must satisfy 3xx=03x - x = 0 for all xAx \in A. However, 3xx=2x03x - x = 2x \neq 0 for x0x \neq 0.
    Hence, RR is not reflexive.
  • Symmetry: For RR to be symmetric, if (x,y)R(x, y) \in R, then (y,x)(y, x) must also belong to RR.
    Check: 3xy=0    3yx0 for xy.3x - y = 0 \implies 3y - x \neq 0 \text{ for } x \neq y. Hence, RR is not symmetric.
  • Transitivity: For RR to be transitive, if (x,y)R(x, y) \in R and (y,z)R(y, z) \in R, then (x,z)(x, z) must also belong to RR.
    Check: 3xy=0 and 3yz=0    3(3x)z=0    9xz=0,3x - y = 0 \text{ and } 3y - z = 0 \implies 3(3x) - z = 0 \implies 9x - z = 0, which satisfies the condition. Hence, RR is transitive.

Thus, the relation RR is neither reflexive nor symmetric but transitive.