Question

Relation between various rate of reaction

$\pm \frac{\Delta C}{\Delta t} = \frac{1}{RT} (\pm \frac{\Delta P}{\Delta t})$

Answer 1

$\pm \frac{\Delta C}{\Delta t} = \frac{1}{RT} (\pm \frac{\Delta P}{\Delta t})$ is derived from the ideal gas law and differentiation with respect to time.

Answer 2

For an ideal gas, the concentration is given by

$c = \frac{n}{V} = \frac{P}{RT}$

Differentiating with respect to time:

$\frac{dc}{dt} = \frac{1}{RT}\frac{dP}{dt}$

Including the sign conventions for consumption or production, we can express the rate as:

$\pm \frac{\Delta C}{\Delta t} = \frac{1}{RT}\left(\pm \frac{\Delta P}{\Delta t}\right)$

Thus, the given relation is valid.