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Question

Physics Question on Ray optics and optical instruments

Refractive index of material is equal to tangent of polarizing angle. It is called:

A

Brewster's law

B

Lambert's law

C

Malus law

D

Bragg's law

Answer

Brewster's law

Explanation

Solution

(a) Brewster's law states that when ordinary light is incident on a transparent surface at polarizing angle (ip)({{i}_{p}}) for that surface, the tangent of angle of polarisation is equal to the refractive index (μ)(\mu ) of the medium of surface, that is, μ=tanip\mu =\tan {{i}_{p}} (b) Lambert's law concerns to rate of absorption of radiation as it travels deeper into a medium. It states that the intensity II of radiation falls off exponentially with distance d in the medium. I=I0expαdI={{I}_{0}}{{\exp }^{-\alpha d}} (a) Brewster's law states that when ordinary light is incident on a transparent surface at polarising angle (ip)\left(i_{p}\right) for that surface, the tangent of angle of polarisation is equal to the refractive index (μ)(\mu) of the medium of surface, that is, (b) Lambert's law concerns to rate of absorption of radiation as it travels deeper into a medium. It states that the intensity II of radiation fails off exponentially with distance dd in the medium. I=I0expadI=I_{0} \exp ^{-a d} (c) Law of Malus states that intensity of light coming out of analyser is proportional to the square of the cosine of the angle between the plane of analyser and polariser. I=I0cos2θI=I_{0}\cos ^{2}\theta (d) According to Bragg's law if a beam of XX-rays of wavelength λ\lambda is directed at a crystal with parallel crystal planes that are distance d apart, then the reflected XX-rays from each plane undergo interference.