Question

Reduction of nitrobenzene in the presence of $\text{Zn/N}{{\text{H}}_{\text{4}}}\text{Cl}$ gives:

• A. azo benzene
• B. aniline
• C. N-phenyl hydroxylamine
• D. hydrazobenzene

Answer 1

Answer: (C)

N-phenyl hydroxylamine

Answer 2

Reduction of nitrobenzene in neutral medium: $Zn/N{{H}_{4}}Cl$ or $Zn/CaC{{l}_{2}}$ reduce a nitro compound to hydroxyl amine. ${{C}_{6}}{{H}_{5}}N{{O}_{2}}+2Zn+4N{{H}_{4}}Cl\xrightarrow{{}}$ $\underset{\text{Phenyl}\,\text{hydroxyl}\,\text{amine}}{\mathop{{{C}_{6}}{{H}_{5}}NHOH}}\,+2ZnC{{l}_{2}}+{{H}_{2}}O+4N{{H}_{3}}$ Phenyl hydroxyl amine