Question

Reduction of acetyl chloride with $H_{2}$ in presence of Pd gives.

• A. $CH_{3}COCH_{3}$
• B. $C_{2}H_{5}OH$
• C. $CH_{3}COOH$
• D. $CH_{3}CHO$

Answer 1

Answer: (D)

$CH_{3}CHO$

Answer 2

$CH_{3}COCl + H_{2}\underset{\text{Reduction}}{\overset{\quad Pd\quad}{\rightarrow}}CH_{3}CHO + HCl$