Question

Reaction of [Co(H2O)6]2+ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t2g-orbitals of the product is _______

Answer 1

$\mathrm{[Co(H_2O)_6]^{2+} \overset{\text{NH}_3}{\underset{\text{O}_2}{\rightarrow}} [Co(NH_3)_6]^{3+} + e^-}$
$Co^{3+} → 3d^6$
NH3 is a strong field ligand
$3d^6 → t^{6}_{2g} eg^0$
Total Number of electrons : 6