Question

Reaction of ${C_6}{H_5}C{H_2}Br$ with aqueous sodium hydroxide follows: ______
A. ${S_N}1$ mechanism
B. ${S_N}2$ mechanism
C. Any of the above two depending upon the temperature of reaction
D. Saytzeff rule

Answer 1

In order to the question, we will see that the given compound ${C_6}{H_5}C{H_2}Br$ is reacting with the aqueous compound. So, we will discuss that in an aqueous medium, which mechanism will follow.

Complete step by step answer:
According to the question, the given reaction between ${C_6}{H_5}C{H_2}Br$ with aqueous sodium hydroxide :
${C_6}{H_5}C{H_2}Br\mathop \to \limits^{aq.NaOH} {C_6}{H_5}C{H_2} - O{H^ - }(stable\,carbocation)$
In an aqueous medium, ${S_N}1$ mechanism follows. In the given reaction between ${C_6}{H_5}C{H_2}Br$ with aqueous sodium hydroxide, stable carbocation get formed as intermediate.
${S_N}1$ reaction mechanism follows a step by step process wherein first, the carbocation is formed from the removal of the leaving group. At that point the carbocation is attacked by the nucleophile. At long last, the deprotonation of the protonated nucleophile happens to give the necessary item.
The ${S_N}1$ response is a nucleophilic replacement response where the rate deciding advance is unimolecular. It is a sort of natural replacement response. ${S_N}1$ represents replacement nucleophilic unimolecular. Accordingly, the rate condition (which expresses that the SN1 response is reliant on the electrophile yet not on the nucleophile) holds in circumstances where the measure of the nucleophile is far more prominent than the measure of the carbocation transitional.

Hence, the correct option is (A.) ${S_N}1$ mechanism .

Note: The ${S_N}2$ reaction mechanism proceeds through a backside attack by the nucleophile on the substrate. The nucleophile approaches the given substrate at a point of the carbon-departing bunch security. The carbon-nucleophile bond structures and carbon-departing bunch bond breaks at the same time through a progress state.