Reaction ( {CH\_3CONH\_2 ->\[NaOBr] }) gives | Chemistry | SolveeIt

Reaction ${CH_3CONH_2 ->[NaOBr] }$ gives

$\ce{CH3Br}$

$\ce{CH4}$

$\ce{CH3COBr}$

$\ce{CH3NH2}$

Answer

$\ce{CH3NH2}$

Explanation

This is Hofmann bromamide reaction in which $1^{\circ}$ amine is obtained having one C atom less than the starting amide.

Chemistry Question on Chemical Reactions