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Question

Question: Reactance of a capacitor of capacitance \(C \mu F\) for ac frequency \(\frac { 400 } { \pi }\) Hz is...

Reactance of a capacitor of capacitance CμFC \mu F for ac frequency 400π\frac { 400 } { \pi } Hz is 25Ω25 \Omega. The value C is

A

50μF50 \mu F

B

25μF25 \mu F

C

100μF100 \mu F

D

75μF75 \mu F

Answer

50μF50 \mu F

Explanation

Solution

XC=12πνCC=12πvXC=12×π×400π×25=50μFX _ { C } = \frac { 1 } { 2 \pi \nu C } \Rightarrow C = \frac { 1 } { 2 \pi v X _ { C } } = \frac { 1 } { 2 \times \pi \times \frac { 400 } { \pi } \times 25 } = 50 \mu F