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Question: \[RCOCl + 2Me_{2}NH \rightarrow A + Me_{2}\overset{+}{NH_{2}Cl^{-}}\] Here A is...

RCOCl+2Me2NH→A+Me2NH2Cl−+RCOCl + 2Me_{2}NH \rightarrow A + Me_{2}\overset{+}{NH_{2}Cl^{-}}

Here A is

A
B

RCONH2RCONH_{2}

C

RCONHMeRCONHMe

D

(RCO)2NH(RCO)_{2}NH

Answer
Explanation

Solution

RCOCl+2Me2NH→RCONMeMe+Me2+N+⥂H2Cl−RCOCl + 2Me_{2}NH \rightarrow RCON\begin{matrix} Me \\ Me \end{matrix} + Me_{2} + \overset{+}{N} ⥂ H_{2}Cl^{-}

Me = Methyl.