Question

Ratio of maximum to minimum intensities is

• A. 5:03
• B. 4:01
• C. 9:01
• D. 3:01

Answer 1

Answer: (C)

9:01

Answer 2

We know, $\frac{I_{1}}{I_{2} } = \frac{w_{1}}{w_{2}} = \frac{A_{1}^{2}}{A_{2}^{2}}$
and $\frac{I_{max}}{I_{min}} = \frac{\left(A_{1} + A_{2}\right)^{2}}{\left(A_{1} - A_{2}\right)^{2}}$
Here, $\frac{w_{1}}{w_{2} } = \frac{0.01}{0.04} = \frac{1}{4} = \frac{A_{1}^{2}}{A_{2}^{2}} or \frac{A_{1}}{A_{2}} = \frac{1}{2}$

or $A_{2} = 2A_{1}$
$\therefore \, \frac{I_{max}}{I_{min}} = \left(\frac{A_{1} + 2A_{1}}{A_{1} - 2A_{1}}\right)^{2} = \left(\frac{3}{-1}\right)^{2} = \frac{9}{1}$