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Question

Question: Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R...

Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R on its axis is-

A

10 10\sqrt { 10 }

B

20 10\sqrt { 10 }

C

2 10\sqrt { 10 }

D

10\sqrt { 10 }

Answer

10 10\sqrt { 10 }

Explanation

Solution

= (R2+x2R2)3/2\left( \frac { \mathrm { R } ^ { 2 } + \mathrm { x } ^ { 2 } } { \mathrm { R } ^ { 2 } } \right) ^ { 3 / 2 }