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Question

Question: Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R...

Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R on its axis is

A

101010 \sqrt { 10 }

B

201020 \sqrt { 10 }

C

2102 \sqrt { 10 }

D

10\sqrt { 10 }

Answer

101010 \sqrt { 10 }

Explanation

Solution

By using Bcentre Baxis =(1+x2r2)3/2\frac { B _ { \text {centre } } } { B _ { \text {axis } } } = \left( 1 + \frac { x ^ { 2 } } { r ^ { 2 } } \right) ^ { 3 / 2 }where x = 3R and r = R

Bcentre Baxis =(10)3/2=1010\frac { B _ { \text {centre } } } { B _ { \text {axis } } } = ( 10 ) ^ { 3 / 2 } = 10 \sqrt { 10 } .