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Question

Physics Question on Atomic Spectra

Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is :

A

931 \frac{9}{31}

B

527 \frac{5}{27}

C

323 \frac{3}{23}

D

729 \frac{7}{29}

Answer

527 \frac{5}{27}

Explanation

Solution

(λlymanλBalmer)max−=(122−132)(112−122)=5/363/4=527\left(\frac{\lambda_{lyman}}{\lambda_{Balmer}}\right)_{max} -= \frac{\left(\frac{1}{2^{2}} - \frac{1}{3^{2}}\right)}{\left(\frac{1}{1^{2}} - \frac{1}{2^{2}}\right)} = \frac{5 / 36 }{3 / 4 } = \frac{5}{27}