Question

Ratio of electric field intensity at P & Q in the shown arrangement is –

• A. 1 : 2
• B. 2 : 1
• C. 1 : 1
• D. 4 : 3

Answer 1

Answer: (C)

1 : 1

Answer 2

E_P =$\frac { \mathrm { kq } } { \mathrm { r } ^ { 2 } }$

E_Q =$\frac { \mathrm { kq } } { ( 2 \mathrm { r } ) ^ { 2 } }$ +=$\frac { 4 \mathrm { kq } } { 4 \mathrm { r } ^ { 2 } }$

E_P : E_Q = 1 : 1