Question

Ratio of active masses of 22 g CO2, 3g H2 and 7g N2 in a gaseous mixture :

• A. 22 : 3 : 7
• B. 0.5 : 3 : 7
• C. 1 : 3 : 1
• D. 1 : 3 : 0.5

Answer 1

Answer: (D)

1 : 3 : 0.5

Answer 2

Moles of CO2 =$\frac { 22 } { 44 }$ =$\frac { 1 } { 2 }$

Moles of H2 = $\frac { 3 } { 2 }$

Moles of N2 = $\frac { 7 } { 28 }$ = $\frac { 1 } { 4 }$

Ratio of active masses = 1/2 : 3/2 : 1/4 or 1 : 3 : 0.5