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Chemistry Question on Chemical Reactions

Rate of dehydration of alcohols follows the order:

A

2∘>1∘>CH3OH>3∘2^{\circ} > 1^{\circ} > CH_{3}OH> 3^{\circ}

B

3∘>2∘>1∘>CH3OH3^{\circ} > 2^{\circ} > 1^{\circ} > CH_{3}OH

C

2∘>3∘>1∘>CH3OH2^{\circ} > 3^{\circ} > 1^{\circ} > CH_{3}OH

D

CH3OH>1∘>2∘>3∘CH_{3}OH>1^{\circ}>2^{\circ}>3^{\circ}

Answer

3∘>2∘>1∘>CH3OH3^{\circ} > 2^{\circ} > 1^{\circ} > CH_{3}OH

Explanation

Solution

The order of dehydration among three type of alcohols is 3∘>2∘>1∘>CH3OH3^{\circ} > 2^{\circ} > 1^{\circ} > CH_{3}OH. This behaviour is related to the relative stabilities of carbocations (3∘>2∘>1∘)\left(3^{\circ} > 2^{\circ} > 1^{\circ} \right).