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Question: Rate of change of torque \(\tau\) with deflection \(\theta\) is maximum for a magnet suspended freel...

Rate of change of torque τ\tau with deflection θ\theta is maximum for a magnet suspended freely in a uniform magnetic field of induction B, when

A

θ=0∘\theta = 0 ^ { \circ }

B

θ=45∘\theta = 45 ^ { \circ }

C

θ=60∘\theta = 60 ^ { \circ }

D

θ=90∘\theta = 90 ^ { \circ }

Answer

θ=0∘\theta = 0 ^ { \circ }

Explanation

Solution

τ=MBHsin⁡θ\tau = M B _ { H } \sin \theta or dτdθ=MBHcos⁡θ\frac { d \tau } { d \theta } = M B _ { H } \cos \theta

This will be maximum. when θ=0o\theta = 0 ^ { o }