Question
Question: Rate law for the reaction \(A + 2B \rightarrow C\) is found to be \[rate = k\lbrack A\rbrack\lbrack...
Rate law for the reaction A+2B→C is found to be
rate=k[A][B]
Concentration of reactant ‘B’ is doubled keeping the concentration of ‘A’ constant the value of rate constant will be________.
A
The same
B
Doubled
C
Quadrupled
D
Halved
Answer
The same
Explanation
Solution
Rate constant of a reaction does not depend upon concentration of the reactants thus it will remain same.