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Question: Rate law for the reaction \(A + 2B \rightarrow C\) is found to be \[rate = k\lbrack A\rbrack\lbrack...

Rate law for the reaction A+2BCA + 2B \rightarrow C is found to be

rate=k[A][B]rate = k\lbrack A\rbrack\lbrack B\rbrack

Concentration of reactant ‘B’ is doubled keeping the concentration of ‘A’ constant the value of rate constant will be________.

A

The same

B

Doubled

C

Quadrupled

D

Halved

Answer

The same

Explanation

Solution

Rate constant of a reaction does not depend upon concentration of the reactants thus it will remain same.