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Question: Rate constant of two reactions are given below identifying their order of reaction. (i) \(k = 5.3 \...

Rate constant of two reactions are given below identifying their order of reaction.

(i) k=5.3×10−2Lmol−1s−1k = 5.3 \times 10^{- 2}Lmol^{- 1}s^{- 1}

(ii) k=3.8×10−4s−1k = 3.8 \times 10^{- 4}s^{- 1}

A

(i) second order, (ii) first order

B

(i) first order, (ii) second order

C

(i) Zero order, (ii) first order

D

(i) Second order , (ii) zero order

Answer

(i) second order, (ii) first order

Explanation

Solution

For second order, rate constant

=molL−1s×1(molL−1)2= \frac{molL^{- 1}}{s} \times \frac{1}{(molL^{- 1})^{2}}

=mol−1Ls−1= mol^{- 1}Ls^{- 1}

For first order, rate constant

=molL−1s×1molL−1=s−1= \frac{molL^{- 1}}{s} \times \frac{1}{molL^{- 1}} = s^{- 1}