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Question: Range of \[y = {x^2} - 5x - 2\] for \[X \in \left[ { - 3,4} \right]\] is A) \[\left[ {\dfrac{{ - ...

Range of y=x25x2y = {x^2} - 5x - 2 for X[3,4]X \in \left[ { - 3,4} \right] is
A) [334,22]\left[ {\dfrac{{ - 33}}{4},22} \right]
B) [334,8]\left[ {\dfrac{{ - 33}}{4}, - 8} \right]
C) [6,4]\left[ { - 6,4} \right]
D) None of these

Explanation

Solution

Finding range is all about finding how a function is behaving in it’s domain or given interval. For this we analyse the function by putting values of x from the given interval.

Complete step by step solution:
Given y=x25x2y = {x^2} - 5x - 2
For x=3x = - 3

y=(3)25(3)2 y=9+152 y=22  \Rightarrow y = {\left( { - 3} \right)^2} - 5\left( { - 3} \right) - 2 \\\ \Rightarrow y = 9 + 15 - 2 \\\ \Rightarrow y = 22 \\\

For x=4x = 4

y=(4)25(4)2 y=1622 y=6  \Rightarrow y = {\left( 4 \right)^2} - 5\left( 4 \right) - 2 \\\ \Rightarrow y = 16 - 22 \\\ \Rightarrow y = - 6 \\\

So, the range should be[6,22]\left[ { - 6,22} \right].

Thus option D is correct.

Additional information:
Range of a function Y is defined as the set of all outcomes for all possible values of x.
In other words mean maximum value of Y to minimum value of Y.
Domain and range of a function is also shown on a graph where on the x-axis we plot range and on the y-axis we plot the domain of a function.
A quadratic equation is of the form ax2+bx+c=0a{x^2} + bx + c = 0.

Note:
Many students get confused in domain and range. domain is all about what values a function can take considering we should avoid indeterminate forms. Whereas Range tells us what values a function can give.