Question

Ram and Shyam are playing a game by throwing a die alternatively till one of them gets a '$'1'$ and wins the game. The probabilities of winning by Ram and Shyam respectively if Ram starts first, is

• A. $\frac{6}{11},\frac{5}{11}$
• B. $\frac{5}{11},\frac{6}{11}$
• C. $\frac{3}{11},\frac{8}{11}$
• D. $\frac{8}{11},\frac{3}{11}$

Answer 1

Answer: (A)

$\frac{6}{11},\frac{5}{11}$

Answer 2

The correct option is (A): $\frac{6}{11},\frac{5}{11}$