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Question

Quantitative Aptitude Question on Ratio and Proportion

Rajesh and Vimal own 20 hectares and 30 hectares of agricultural land, respectively, which are entirely covered by wheat and mustard crops. The cultivation area of wheat and mustard in the land owned by Vimal are in the ratio of 5 : 3. If the total cultivation area of wheat and mustard are in the ratio 11 : 9, then the ratio of cultivation area of wheat and mustard in the land owned by Rajesh is

A

7 : 9

B

3 : 7

C

1 : 1

D

4 : 3

Answer

7 : 9

Explanation

Solution

Let the area of wheat and mustard cultivated by Vimal be represented as WvW_v and MvM_v, respectively. We are given that the ratio of wheat to mustard in Vimal's land is 5 : 3. Therefore, we can express this as:
WvMv=53orWv=53Mv\frac{W_v}{M_v} = \frac{5}{3} \quad \text{or} \quad W_v = \frac{5}{3} M_v
We also know that the total area of Vimal's land is 30 hectares, so:
Wv+Mv=30W_v + M_v = 30
Substitute Wv=53MvW_v = \frac{5}{3} M_v into the equation:
53Mv+Mv=30\frac{5}{3} M_v + M_v = 30
Simplify:
83Mv=30    Mv=30×38=11.25\frac{8}{3} M_v = 30 \implies M_v = 30 \times \frac{3}{8} = 11.25
Now, substitute Mv=11.25M_v = 11.25 back into Wv=53MvW_v = \frac{5}{3} M_v:
Wv=53×11.25=18.75W_v = \frac{5}{3} \times 11.25 = 18.75
So, Vimal's land has Wv=18.75W_v = 18.75 hectares of wheat and Mv=11.25M_v = 11.25 hectares of mustard.

Next, let's consider Rajesh's land, where the total area of wheat and mustard is divided. The total area of Rajesh's land is 20 hectares, so:
Wr+Mr=20W_r + M_r = 20
We are also told that the overall ratio of wheat to mustard across both Rajesh's and Vimal's lands is 11 : 9, i.e.,
Wv+WrMv+Mr=119\frac{W_v + W_r}{M_v + M_r} = \frac{11}{9}
Substitute the values of Wv=18.75W_v = 18.75 and Mv=11.25M_v = 11.25 into the equation:
18.75+Wr11.25+Mr=119\frac{18.75 + W_r}{11.25 + M_r} = \frac{11}{9}
Cross-multiply to solve for WrW_r and MrM_r:
9(18.75+Wr)=11(11.25+Mr)9(18.75 + W_r) = 11(11.25 + M_r)
Simplifying:
9Wr+168.75=11Mr+123.759W_r + 168.75 = 11M_r + 123.75
9Wr11Mr=459W_r - 11M_r = -45
We also have the equation Wr+Mr=20W_r + M_r = 20. Now, solve this system of equations. From Wr+Mr=20W_r + M_r = 20, express WrW_r as:
Wr=20MrW_r = 20 - M_r
Substitute into the equation 9Wr11Mr=459W_r - 11M_r = -45:
9(20Mr)11Mr=459(20 - M_r) - 11M_r = -45
Simplify:
1809Mr11Mr=45180 - 9M_r - 11M_r = -45
18020Mr=45    20Mr=225    Mr=11.25180 - 20M_r = -45 \implies -20M_r = -225 \implies M_r = 11.25
Substitute Mr=11.25M_r = 11.25 into Wr+Mr=20W_r + M_r = 20:
Wr=2011.25=8.75W_r = 20 - 11.25 = 8.75
Finally, the ratio of the areas of wheat to mustard in Rajesh's land is:
WrMr=8.7511.25=79\frac{W_r}{M_r} = \frac{8.75}{11.25} = \frac{7}{9}
Thus, the correct answer is Option (1).