Question
Quantitative Aptitude Question on Ratio and Proportion
Rajesh and Vimal own 20 hectares and 30 hectares of agricultural land, respectively, which are entirely covered by wheat and mustard crops. The cultivation area of wheat and mustard in the land owned by Vimal are in the ratio of 5 : 3. If the total cultivation area of wheat and mustard are in the ratio 11 : 9, then the ratio of cultivation area of wheat and mustard in the land owned by Rajesh is
7 : 9
3 : 7
1 : 1
4 : 3
7 : 9
Solution
Let the area of wheat and mustard cultivated by Vimal be represented as Wv and Mv, respectively. We are given that the ratio of wheat to mustard in Vimal's land is 5 : 3. Therefore, we can express this as:
MvWv=35orWv=35Mv
We also know that the total area of Vimal's land is 30 hectares, so:
Wv+Mv=30
Substitute Wv=35Mv into the equation:
35Mv+Mv=30
Simplify:
38Mv=30⟹Mv=30×83=11.25
Now, substitute Mv=11.25 back into Wv=35Mv:
Wv=35×11.25=18.75
So, Vimal's land has Wv=18.75 hectares of wheat and Mv=11.25 hectares of mustard.
Next, let's consider Rajesh's land, where the total area of wheat and mustard is divided. The total area of Rajesh's land is 20 hectares, so:
Wr+Mr=20
We are also told that the overall ratio of wheat to mustard across both Rajesh's and Vimal's lands is 11 : 9, i.e.,
Mv+MrWv+Wr=911
Substitute the values of Wv=18.75 and Mv=11.25 into the equation:
11.25+Mr18.75+Wr=911
Cross-multiply to solve for Wr and Mr:
9(18.75+Wr)=11(11.25+Mr)
Simplifying:
9Wr+168.75=11Mr+123.75
9Wr−11Mr=−45
We also have the equation Wr+Mr=20. Now, solve this system of equations. From Wr+Mr=20, express Wr as:
Wr=20−Mr
Substitute into the equation 9Wr−11Mr=−45:
9(20−Mr)−11Mr=−45
Simplify:
180−9Mr−11Mr=−45
180−20Mr=−45⟹−20Mr=−225⟹Mr=11.25
Substitute Mr=11.25 into Wr+Mr=20:
Wr=20−11.25=8.75
Finally, the ratio of the areas of wheat to mustard in Rajesh's land is:
MrWr=11.258.75=97
Thus, the correct answer is Option (1).