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Question: Rain is falling with the speed of \[25\sqrt 3 m/s\] vertically. The wind blows west to east at a spe...

Rain is falling with the speed of 253m/s25\sqrt 3 m/s vertically. The wind blows west to east at a speed of 25m/s25m/s . Find the velocity of rain as experienced by a person standing on ground:
A.50m/s50m/s
B.100m/s100m/s
C.0m/s0m/s
D.90m/s90m/s

Explanation

Solution

The velocity of rain as experienced by a person is the resultant of the speed of the rain falling vertically downwards and the speed of the wind taking the ground as a reference frame.

Complete answer:
Rain is falling vertically downwards with the speed (vr{v _r}) of 253m/s25\sqrt 3 m/s . So vr=253j\overrightarrow {{v_r}} = 25\sqrt 3 j m/sm/s .
The wind is blowing from west to east with the speed (vw{v_w}) of 25m/s25m/s . So vw=25i\overrightarrow {{v_w}} = 25i m/sm/s .
If the velocity of the rain as experienced by a person standing on ground is vrw{v_{rw}} then we can represent it by the following vector diagram.

Here θ\theta is the angle between the resultant vector and the ground.
So,
tanθ=vrvw tanθ=25325=3  \tan \theta = \dfrac{{\overrightarrow {{v_r}} }}{{\overrightarrow {{v_w}} }} \\\ \Rightarrow \tan \theta = \dfrac{{25\sqrt 3 }}{{25}} = \sqrt 3 \\\
Now θ=π3\theta = \dfrac{\pi }{3}
According to the Triangle law of vector addition states that when two vectors are represented as two sides of the triangle with the order of the magnitude and direction, then the third side of the triangle represents the magnitude and direction of the resultant vector.
Applying Triangle law, we can say vrw=vr+vw\overrightarrow {{v_{rw}}} = \overrightarrow {{v_r}} + \overrightarrow {{v_w}}
So, vrw=25i+253j\overrightarrow {{v_{rw}}} = 25i + 25\sqrt 3 j m/sm/s
Now vrw=(25)2+(253)2\left| {\overrightarrow {{v_{rw}}} } \right| = \sqrt {{{(25)}^2} + {{(25\sqrt 3 )}^2}} m/sm/s
=4×252= \sqrt {4 \times {{25}^2}} m/sm/s
=50= 50 m/sm/s
Therefore, the velocity of the rain as experienced by a person standing on ground is 50m/s50m/s and it makes angle π3\dfrac{\pi }{3} with the ground.

So, the correct answer is option A.

Note:
Relative velocity is the velocity of an object that is observed from a particular reference frame. It varies with the choice of the reference frame. Drawing a vector diagram, showing the velocity vectors can help in understanding the relative velocity.