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Question

Quantitative Aptitude Question on Time and Work

Rahul, Rakshita and Gurmeet, working together, would have taken more than 7 days to finish a job. On the other hand, Rahul and Gurmeet, working together would have taken less than 15 days to finish the job. However, they all worked together for 6 days, followed by Rakshita, who worked alone for 3 more days to finish the job. If Rakshita had worked alone on the job then the number of days she would have taken to finish the job, cannot be

A

16

B

21

C

17

D

20

Answer

21

Explanation

Solution

Let a, b, and c be the daily work units completed by Rahul, Rakshita, and Gurmeet, respectively. The total work units would be W.
Therefore, we can conclude that 7(a+b+c)<W7(a+b+c) < W (because Rahul, Rakshita, and Gurmeet would have needed more than 7 days to complete a task if they had worked together).
Similar to this, we can state that 15(a+c)>W15(a+c) > W, meaning that Rahul and Gurmeet could have completed the task in less than 15 days if they had collaborated.
Now, when we contrast these two inequalities, we obtain: 15(a+c)<W<7(a+b+c)15(a+c) < W < 7(a+b+c)
It is also reported that Rakshita worked alone for three more days to complete the task after they had all collaborated for six days. W=6(a+b+c)+3bW = 6(a+b+c)+3b represents the total amount of work completed.
Thus, we can state that 6(a+b+c)+3b<15(a+c)=7(a+b+c).6(a+b+c)+3b < 15(a+c) = 7(a+b+c).
A+b+c<3bA+b+c < 3b
7(a+b+c)<21b,⇒ 7(a+b+c) < 21b, and 15b<15(a+c)15b < 15(a+c) imply that (a+b+c)<3b(a+b+c) < 3b
a+c<2b⇒ a+c < 2b and 9b<9(a+c)9b < 9(a+c)
b<a+c.⇒ b < a+c.
Therefore, the days needed for B must fall between 15 and 21 (inclusive).
Therefore, choice B is the right one.