Question

Radon has $3.8$ days as its half life how much radon will be left out of 15 mg mass after 38 days?

• A. $1.05$mg
• B. $0.015$mg
• C. $0.231$ mg
• D. $0.50$ mg

Answer 1

Answer: (B)

$0.015$mg

Answer 2

: here , $n = \frac{t}{T_{1/2}} = \frac{38}{3.8} = 10$

}{= \frac{15}{1024} = 0.015mg}$$