Radius of (n^{th}) orbit of (H)-like particles is proportion... | Physics | SolveeIt | Solveeit

Today, August 18

Question

Radius of $n^{th}$ orbit of $H$ -like particles is proportional to

A

$n^2$

B

$n^2Z$

C

$n^2/Z^2$

D

$n^2/Z$

Answer

$n^2/Z$

Explanation

Solution

$r_n = 0.529 \,n^2/Z$ $r_n \propto n^2/Z$ .