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Question: Radius of circle \(( x - 5 ) ( x - 1 ) + ( y - 7 ) ( y - 4 ) = 0\) is....

Radius of circle (x−5)(x−1)+(y−7)(y−4)=0( x - 5 ) ( x - 1 ) + ( y - 7 ) ( y - 4 ) = 0 is.

A

3

B

4

C

5/2

D

7/2

Answer

5/2

Explanation

Solution

Extremities of diameter are (5, 7) and (1, 4) and radius is half of the distance between them

=12(4)2+(3)2=52= \frac { 1 } { 2 } \sqrt { ( 4 ) ^ { 2 } + ( 3 ) ^ { 2 } } = \frac { 5 } { 2 }