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Question: Radius of a circle passing through the origin and touching the parabola y<sup>2</sup> = 4x at (1, 2)...

Radius of a circle passing through the origin and touching the parabola y2 = 4x at (1, 2) is

A

56\frac{5}{6}

B

526\frac{5\sqrt{2}}{6}

C

52\frac{5}{\sqrt{2}}

D

None of these

Answer

52\frac{5}{\sqrt{2}}

Explanation

Solution

Equation of normal at the point (1, 2) w.r.t. the parabola

y2 = 4x is x + y –3 = 0.

Let the centre of the circle be (α, β) ⇒ α + β – 3 = 0. …. (1)

Also (α –1)2 + (β –2)2 = α2 + β2 i.e 2α + 4β = 5.

From (1) and (2), α = 7/2 and β = –1/2.